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Q. $20\, \mu C$ charge is placed inside a closed surface; then flux linked with the surface is $\phi .$ If $80\, \mu C$ more charge is put inside the surface then change in flux is :-

Solution:

$\phi \propto q$ ...(i)
After addition flux becomes $\phi'$.
$\phi' \propto q '$ ...(ii)
$\frac{\phi'}{\phi}=\frac{ q ^{1}}{ q }=\frac{100}{20}=5$
$\phi'=5 \phi$
change influx $\Delta \phi=\phi'-\phi=4 \phi$