1. Tardigrade
  2. Question
  3. Chemistry
  4. 20 mL of 0.2 M NaOH is added to 50 mL of 0.2 M acetic acid. The pH of this solution after mixing is (Ka = 1.8 × 10-5)

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. $20\, mL$ of $0.2\, M \,NaOH$ is added to $50\, mL$ of $0.2\, M$ acetic acid. The pH of this solution after mixing is $(Ka = 1.8 \times 10^{-5})$

VITEEEVITEEE 2011

Solution:

$\ce{NaOH + CH3COOH -> CH3COONa + H2O}$
image
$ pH =-\log \left(1.8 \times 10^{-5}\right)+\log \frac{4 / 70}{6 / 70} $
$=4.56$