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  4. 20 ml of 0.02 M KMnO4 was required to completely oxidise 10 ml of oxalic acid solution. What is the molarity of the oxalic acid solution?

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Q. 20 ml of $0.02 \,M\, KMnO_{4}$ was required to completely oxidise 10 ml of oxalic acid solution. What is the molarity of the oxalic acid solution?

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Solution:

The concerned reaction is
$2KMnO_{4} +3H_{2}SO_{4}+5(COOH)_{2} \to K_{2}SO_{4}+2MnSO_{4}+10CO_{2}+8H_{2}O$
$\begin{matrix}[{\text{For}} KMnO_{4}]&[{\text{For oxalic acid}}]\\ V_{1}=20\,ml&V_{2}=10\,ml\\ M_{1}=0.02\,M&M_{2}=?\end{matrix}$
$n_{1}=2, \, n_{2}=5$
$\frac{M_{1} V_{1}}{n_{1}}=\frac{M_{2} V_{2}}{n_{2}}$
$\frac{0.02\times20}{2}=\frac{M_{2}\times10}{5}$
$M_{2}=\frac{0.02\times20\times5}{10\times2}=0.1\,M$