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  4. 20 mL 0.1( N ) acetic acid is mixed with 10 mL 0.1( N ) solution of NaOH. The pH of the resulting solution is ( p Ka. of acetic acid is 4.74 )

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Q. $20\, mL\, 0.1( N )$ acetic acid is mixed with $10\, mL$ $0.1( N )$ solution of $NaOH$. The $pH$ of the resulting solution is $\left( p K_{a}\right.$ of acetic acid is $4.74$ )

WBJEEWBJEE 2012Equilibrium

Solution:

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From Henderson's equation,
$pH = p K_{a}+\log \frac{\left[ CH _{3} COONa \right]}{\left[ CH _{3} COOH \right]}$
$=4.74+\log \frac{1}{1}=4.74$