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  4. 20.0 kg of N2(g) and 3.0 kg of H2(g) are mixed to produce NH3(g). The amount of NH3(g) formed is

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Q. $20.0 \,kg$ of $N_2(g)$ and $3.0\, kg$ of $H_2(g)$ are mixed to produce $NH_3(g)$. The amount of $NH_3(g)$ formed is

KEAMKEAM 2011Some Basic Concepts of Chemistry

Solution:

$N_2+3 H_2 \rightleftharpoons 2 N_3$
$\frac{20 \times 10^3 g}{28} \frac{3 \times 10^3 g}{2}$
$=711.2$ mole. $1500$ mole
L. $R=\frac{711.2}{1}=\frac{1500}{3}$
3 mole $\longrightarrow 2$ mole
1 mole $\longrightarrow \frac{2}{5}$ mole
1500 mole $\longrightarrow \frac{2}{3}$ mole
$=1000$ mole
$17 \times 1000$
$=17\, kg$