Question

$2$ mole of $N _{2} H _{4}$ loses $16$ mole of electron is being converted to a new compound $X$. Assuming that all of the $N$ appears in the new compound. The oxidation state of $'N'$ in $X$ is _______.

Answer 1

$2\, N_2H_4 \to X+16\,e^{-}$

2 moles $\,\,\,\,\,\,\, \, \, \, $ 16 moles

or 1 mole $\,\,\,\,\,\,\, \, \, \, $ 8 moles

Or 1 mole of N loses 4 mole of $e^{-}$

$N ^{2-} \to N ^{ a }+4 e ^{-}$

(O.N of $N$ in $\overset{x}{N_{2}}\, \overset{+1}{H_{4}}$ is $2x+4=0$

$\Rightarrow x=-2$

$\therefore a-(-2)=4$

$\Rightarrow a=+2$