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Chemistry
2 mole of an ideal gas undergo isothermal and reversible expansion from 2 litre to 20 litre at 127° C the work done by the gas is
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Q. $2 $ mole of an ideal gas undergo isothermal and reversible expansion from $2$ litre to $20$ litre at $127^{\circ} C$ the work done by the gas is
A
-25.2 kJ
0%
B
-15.3 kJ
100%
C
-7.5 kJ
0%
D
-35.1 kJ
0%
Solution:
$ \omega =-2.303\, n\, R T \log \frac{V_{2}}{v_{1}} $
$=-2.303 \times 2+8.31 \times 400 \times \log \frac{20}{2} $
$=-15.3\, KJ $