1. Tardigrade
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  3. Chemistry
  4. 2 HC ≡ CH xrightarrow Cu 2++ O 2( A ) xrightarrow[ HCl]1 mol (B) Compounds (A) and (B) are:

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Q. $2 HC \equiv CH \xrightarrow{ Cu ^{2+}+ O _2}( A ) \xrightarrow[ HCl]{1 mol }(B)$
Compounds (A) and (B) are:

Hydrocarbons

Solution:

Correct answer is (b)