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Q. $2$ grams of a metal hydroxide, on ignition, gave $1.51$ grams of oxide. Equivalent weight of metal is

Some Basic Concepts of Chemistry

Solution:

$\frac{w_{1}}{w_{2}} = \frac{E_{1}}{E_{2}}$
$\frac{2}{1.51} = \frac{Eq \,wt. \,of \,metal\, + \,Eq. \,wt.\, of \,hydroxideion}{Eq. \,wt. \,of \,metal \,+ \,Eq.\, wt. \,of \,oxygen}$
$E = 20
\frac{2}{1.15} = \frac{E\,+\,17}{E\,+\,8}$