Question

$2\, g$ of hydrogen combine with $16\, g$ of oxygen to form water and with $6\, g$ of carbon to form methane. In carbon dioxide $12\, g$ of carbon are combined with $32\, g$ of oxygen. These figures illustrate the law of

• A. Multiple proportions
• B. Constant proportions
• C. Reciprocal proportions
• D. Conservation of mass

Answer 1

Answer: (C)

we have
$2\, g$ of $H$ combine with $16\, g$ of $O _{2}$ to form $H _{2} O$
$2\, g$ of $H$ combine with $6\, g$ of $C$ to form $CH _{4}$

this illustrate law of Reciprocal proportion which states that If two different element combine separately with same wt of third element the ratio of the masses in which they do so are either the Same or Simple multiple of mass ratio in which they combine