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  4. 2-Bromopentane is heated with potassium ethoxide in ethanol. The major product obtained is

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Q. 2-Bromopentane is heated with potassium ethoxide in ethanol. The major product obtained is

Haloalkanes and Haloarenes

Solution:

Potassium ethoxide is a strong base, and 2- bromopentane is a 2ยบ bromide, so elimination raction predominates
$CH_3CH(Br)CH_2CH_2CH_3 \xrightarrow{OC_2H^-_5} \underset{\text{Pentene - 2(major) trans}}{CH_3CH = CHCH_2CH_3} + \underset{\text{Pentene 1(min or) cis}}{CH_2 CHCH_2CH_2CH_3} $ Since trans- alkene is more stable than cis.Thus trans-pentene -2 is the main product.