Q. $2^{1 / 4} \cdot 4^{1 / 8} \cdot 8^{1 / 16} \cdot 16^{1 / 32} \cdot 32^{1 / 64} \ldots \ldots . \infty$ is equal to
Sequences and Series
Solution:
$E =2^{1 / 4} \cdot 4^{1 / 8} \cdot 8^{1 / 16} \cdot 16^{1 / 32} \cdot 32^{1 / 64}$
