Question

$2.0\, g$ of $H _{2}$ gas is adsorbed on $2.5 \,g$ of platinum powder at $300\, K$ and $1$ bar pressure. The volume of the gas adsorbed per gram of the adsorbent is _______$mL$.
(Given : $R =0.083\, L$ bar $K ^{-1} \,mol ^{-1}$ )

Answer 1

Volume of $H _{2}=\frac{ nRT }{ p }$
$=\frac{2}{2} \times \frac{0.083 \times 300}{1}$
$=24.92\, L$
$=24900\, mL$
So $1 \,g$ platinum adsorb $=\frac{24900}{2.5} mLH _{2}$
$=9960$