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  4. 2.0 g of a non-electrolyte dissolved in 100 g of benzene lowers the freezing point of benzene by 1.2 K. The freezing point depression constant of benzene is 5.12 K kg mol -1. The molar mass of the solute is

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Q. $2.0\, g$ of a non-electrolyte dissolved in $100\, g$ of benzene lowers the freezing point of benzene by $1.2\,K$. The freezing point depression constant of benzene is $5.12\, K\, kg\, mol ^{-1}$. The molar mass of the solute is

TS EAMCET 2018

Solution:

$\Delta T_{f}=K_{f} m=K_{f} \times \frac{W_{2}}{M_{2}} \times \frac{1000}{w_{1}}$

$1 \cdot 2=\frac{5 \cdot 12 \times 2 \times 1000}{M_{2} \times 100}$

$M_{2}=85\, g\, mol ^{-1}$