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Q. 18 g of ice is converted into water at $ 0{}^\circ C $ and 1 atm. The entropies of $ {{H}_{2}}O\,(s) $ and $ {{H}_{2}}O\,(l) $ are 38.2 and $ 60\,J\text{/}mol\text{ }K $ respectively. The enthalpy change for this conversion is

CMC MedicalCMC Medical 2015

Solution:

At equilibrium $ \Delta H=T\cdot \Delta \,S $ $ {{H}_{2}}O(s)\xrightarrow{{}}{{H}_{2}}O(l) $ $ \Delta S={{S}_{{{H}_{2}}O(l)}}-{{S}_{{{H}_{2}}O(s)}} $ $ =(60-38.2)\,J\text{/}mol\text{-}K=21.8\,J\text{/}mol\text{-}K $ $ \Delta H=273\times (21.8)=5951.4\,J\text{/}mol $