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  4. 18 g of glucose is added to 178.2 g of water. The vapour pressure of water for this aqueous solution at 100° C is

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Q. 18 g of glucose is added to 178.2 g of water. The vapour pressure of water for this aqueous solution at $ 100{}^\circ C $ is

BHUBHU 2011

Solution:

$ \frac{{{p}^{o}}-{{p}_{s}}}{{{p}^{o}}}=\frac{n}{N} $
$ \frac{760-{{p}_{s}}}{760}=\frac{\frac{18}{180}}{\frac{178.2}{18}}=\frac{0.1}{9.9} $
$ 760-{{p}_{s}}=\frac{1}{99}\times 760 $
$ {{p}_{s}}=760-7.6=752.4 $