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  4. 18 g of glucose (C6H12O6) is added to 178.2 g of water. The vapour pressure of water for this aqueous solution at 100°C

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Q. 18 g of glucose $(C_6H_{12}O_6)$ is added to 178.2 g of water. The vapour pressure of water for this aqueous solution at 100$^\circ$C

J & K CETJ & K CET 2010Solutions

Solution:

$\frac{p^\circ - p_s}{p^\circ} = \frac{n_2}{n_1} = \frac{w_2/M_2}{w_1/M_1}$
$\therefore $ $\frac{760 - p_s}{p_s} = \frac{18/180}{178.2/18} $ or $\frac{760}{p_s} - 1 = \frac{18}{1782}$
or $\frac{760}{p_s} = \frac{18}{1782} + 1 = \frac{1820}{1782} $ or $p_s = 752.4 $ torr