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  4. The number of geometric isomers that can exist for square planar [ Pt ( Cl )( py )( NH 3)( NH 2 OH )]+is (py = pyridine)

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Q. The number of geometric isomers that can exist for square planar $\left[ Pt ( Cl )( py )\left( NH _{3}\right)\left( NH _{2} OH \right)\right]^{+}$is________ (py = pyridine)

Coordination Compounds

Solution:

For square planar complexes of the type $[ Mabcd ]^{n \pm}$ where all the four ligands are different, three geometrical isomers are possible.
So, for the given square planar complex $\left[ Pt ( Cl )( py )\left( NH _{3}\right)\left( NH _{2} OH \right)\right]^{+}$, following three geometrical isomers are possible:
image
where $a= Cl , b=p y, c= NH _{3}$ and $d= NH _{2} OH$.