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Q. $120$ grams of an organic compound contains $40\%C$ by mass, $8g$ -atom of $H$ and $64$ grams of oxygen, The molecular formula of compound is :

NTA AbhyasNTA Abhyas 2020

Solution:

$n_{C}=\frac{48}{12}=4$
$n_{H}=\frac{8}{1}=8$
$n_{D}=\frac{64}{16}=4$
In $60g;n_{C}:n_{H}:n_{O}$
$2:4:2$
$CH_{3}COOH$