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Q. $12$ litre of $H _{2}$ and $11.2$ litre of $Cl _{2}$ are mixed and exploded. The volume of $H _{2}$ in the mixture is -

Some Basic Concepts of Chemistry

Solution:

$\underset{1\,mole}{H_2} + \underset{1\,mole}{Cl_2} \rightarrow \underset{2\,mole}{2HCl}$
$11.2$ litre at $NTP$ gas has $=0.5$ mole $Cl _{2}$
$11.2=12$ litre $NTP =0.5$ mole $H _{2}$
$0.8$ litre $H _{2}=$ remaining
$1$ mole $HCl =22.4$ litre