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  4. 12 g of a nonvolatile solute dissolved in 108 g of water produces the relative lowering of vapour pressure of 0.1. The molecular mass of the solute is :

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Q. $12\, g$ of a nonvolatile solute dissolved in $108\, g$ of water produces the relative lowering of vapour pressure of $0.1.$ The molecular mass of the solute is :

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Solution:

$\frac{P^{o}-P_{s}}{P^{o}} = \frac{n}{N} = \frac{w}{m}\times \frac{M}{W}$
$0.1= \frac{12}{m} \times \frac{18}{108}$
$m = \frac{12\times18}{0.1\times108} = 20$