1. Tardigrade
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  3. Physics
  4. 1000 N force is required to lift a hook and 10000 N force is required to lift a load slowly. Find power required to lift hook with load with speed v=0.5 m / sec.

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Q. $1000\, N$ force is required to lift a hook and $10000\, N$ force is required to lift a load slowly. Find power required to lift hook with load with speed $v=0.5 \,m / sec$.

JIPMERJIPMER 2018

Solution:


P = F.V = (1000 + 10000)0.5
$= \frac{11000}{2}$ = 5500 = 5.5 kW