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  4. 100 tons of Fe2O3 containing 20 % impurities will give iron by reduction with H2 equal to

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Q. $100$ tons of $Fe_2O_3$ containing $20\%$ impurities will give iron by reduction with $H_2$ equal to

Some Basic Concepts of Chemistry

Solution:

$\underset{160 g }{ Fe _2 O _3}+3 H _2 \rightarrow \underset{112 g }{2 Fe }+3 H _2$
$Fe _2 O _3$ given $=100$ tons $-20$ tons impurities $=80$ tons
Fe obtained $=\frac{112}{160} \times 80=56$ tons