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  4. 100 mL of mixture of NaOH and Na 2 SO 4 is neutralized by 10 mL of 0.5 M H 2 SO 4. Hence, NaOH in 100 mL solution is

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Q. $100 \,mL$ of mixture of $NaOH$ and $Na _2 SO _4$ is neutralized by $10 \,mL$ of $0.5 \, M \, H _2 SO _4$. Hence, $NaOH$ in $100 \,mL$ solution is

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Solution:

$Na _2 SO _4$ does not react
$N( NaOH )=0.1=4 \, g\, L ^{-1}$
$=0.4\, g$ per $100\, mL$