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Q.
$100 \,mL$ of $HCl + 35\, mL$ of $NaOH$, colour of methyl orange in the solution will be
AFMCAFMC 2010
Solution:
When $100\, mL\, HCl$ is added to $35 \,mL\, NaOH$, $35\, mL\, HCl$ is utilised to neutralise $NaOH$, while $65\, mL\, HCl$ remains as such. Hence, the solution becomes acidic. In acid solution, the colour of methyl orange (indicator) is red due to presence of $Me ^{+}$ions as
$\underset{\text{methyl orange (yellow)}}{MeOH} \rightleftharpoons \underset{\text{red}}{Me^+} + OH^-$