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Chemistry
100 ml of 0.1 N NaOH is mixed with 100 ml of 0.1 N H 2 SO 4. The pH of the resultant solution is
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Q. $100\, ml$ of $0.1 \,N \,NaOH$ is mixed with $100\, ml$ of $0.1 \,N \,H _{2} SO _{4}$. The $pH$ of the resultant solution is
Equilibrium
A
$ < 7$
38%
B
$ >7$
8%
C
$ = 7$
53%
D
Cannot be predicted
1%
Solution:
$\because$ Numher of $g$ equivalents of acid
$=$ Number of $g$ equivalents of base
$\Rightarrow pH =7$ and solution is neutral