Question

$100 \, mL$ of $0.1 \, M \, NaHC _2 O _4$ is neutralised by $V_1 \, mL$ of $0.1 \, M \, NaOH$ and $V_2 \, mL$ of a $M \, KMnO _4$ separately, then for complete neutralization :

• A. Volume of $NaOH$ required $=200 \, mL$
• B. If $M$ of $KMnO _4$ is $0.1 \, M$ then $\frac{V_1}{V_2}=5: 2$
• C. If $M$ of $KMnO _4$ is $0.1 \, M$ then $V_2=40 \, mL$
• D. If $M$ of $KMnO _4$ is $0.2 \, M$ then $V_2=2 \, mL$

Answer 1

Answer: (B), (C)

Correct answer is (b) If $M$ of $KMnO _4$ is $0.1 \, M$ then $\frac{V_1}{V_2}=5: 2$Correct answer is (c) If $M$ of $KMnO _4$ is $0.1 \, M$ then $V_2=40 \, mL$