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Q. $100\, mL$ each of $0.5\, N\, NaOH ,\, N / 5\, HCl$ and $N / 10\, H _{2} SO _{4}$ are mixed together. The resulting solution will be:

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Solution:

Meq. of $NaOH =100 \times 0.5=50$
Meq. of $HCl =(1 / 5) \times 100=20$
Meq. of $H _{2} SO _{4}=(1 / 10) \times 100=10$
Total Meq. of acid $=20+10=30$
Total Meq. of $NaOH =50$;
$\therefore $ Meq. of $NaOH$ left $=50-30=20$
Thus, resulting solution will be alkaline,