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  4. 10 mL of 2(M) NaOH solution is added to 200 mL of 0.5 (M) of NaOH solution. What is the final concentration ?

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Q. $10\, mL$ of $2(M)$ $NaOH$ solution is added to $200\, mL$ of $0.5 (M)$ of $NaOH$ solution. What is the final concentration ?

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Solution:

From molarity equation
$M_{1} V_{1}+M_{2} V_{2} =MV_{\left(total\right)}$
$2\times\frac{10}{1000}+0.5\times\frac{200}{1000}=M \times\frac{210}{1000}$
$120=M \times210$
$M=\frac{120}{210}=0.57 M$