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  4. 10 g of water at 70° C is mixed with 5 g of water at 30° C . Find the temperature of the mixture in equilibrium.

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Q. 10 g of water at $ 70{}^\circ C $ is mixed with 5 g of water at $ 30{}^\circ C $ . Find the temperature of the mixture in equilibrium.

EAMCETEAMCET 2008

Solution:

Let $ t{{\,}^{o}}C $ be the temperature of the mixture. From Calorimetry principle, Heat given by 10 g of water = Heat taken by 5 g of water or $ {{m}_{1}}{{s}_{w}}\Delta {{T}_{1}}={{m}_{2}}{{s}_{w}}\Delta T $ $ \therefore $ $ 10\times (70-t)=5\times (t-30) $ $ \therefore $ $ t=56.67{{\,}^{o}}C $