1. Tardigrade
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  3. Physics
  4. 10 g of ice cubes at 0° C is released in a tumbler containing water (water equivalent 55 g ) at 40° C. Assuming that negligible heat is taken from surroundings, the temperature of water in the tumbler becomes (L=80 cal g -1) :

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Q. $10\, g$ of ice cubes at $0^{\circ} C$ is released in a tumbler containing water (water equivalent $55\, g$ ) at $40^{\circ} C$. Assuming that negligible heat is taken from surroundings, the temperature of water in the tumbler becomes $\left(L=80\, cal\, g ^{-1}\right)$ :

Thermal Properties of Matter

Solution:

According to principle of calorimetry,
Let final temperature is $T$
$\Rightarrow 55 \times 1 \times(40-T) =(10 \times 80)+10 \times 1 \times(T-0)$
$\Rightarrow 2200-55\, T =800+10\, T$
$\Rightarrow 65\, T =1400$
$\Rightarrow T =21.5^{\circ} C$