Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. $10 \,g$ of hydrogen and $32 \,g$ of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be

Some Basic Concepts of Chemistry

Solution:

$\underset{2\,g\, 1\,mol}{H_{2}}+\underset{16\,g 0.5\,mol}{1/2 O_{2}} \to \underset{18\,g 1\,mol}{H_{2}O}$

$10 \,g$ of $H _{2}=5 mol$ and $32 g$ of $O _{2}=1 mol$

$\therefore $ In this reaction, oxygen is the limiting reagent so amount of $H _{2} O$ produced depends on amount of $O _{2}$.

Since $0.5 mol$ of $O _{2}$ gives $1 mol H _{2} O$

$\therefore 1 \,mol$ of $O _{2}$ will give $2 \,mol \,H _{2} O$