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  4. 10 g of a sample of a mixture of CaCl 2 and NaCl is treated to precipitate all the calcium as CaCO 3. This CaCO 3 is heated to convert all the Ca to CaO and the final mass of CaO is 1.62 g. The precent by mass of CaCl 2 in the original mixture is

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Q. $10 \,g$ of a sample of a mixture of $CaCl _2$ and $NaCl$ is treated to precipitate all the calcium as $CaCO _3$. This $CaCO _3$ is heated to convert all the $Ca$ to $CaO$ and the final mass of $CaO$ is $1.62 \,g$. The precent by mass of $CaCl _2$ in the original mixture is

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Solution:

$CaCl _2+ NaCl =10 \,g$
Let weight of $CaCl _2=x g$
image
$Mol$ of $CaO =\frac{1.62}{56}$
$\therefore \frac{x}{111}=\frac{1.62}{56} $
$x=3.21 \,g$
$\%$ of $CaCl _2=\frac{3.21}{10} \times 100=32.1 \%$