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  4. 10 cm3 of 0.1 N monobasic acid requires 15 cm3 of sodium hydroxide solution whose normality is

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Q. $10 \,cm^3$ of $0.1\, N$ monobasic acid requires $15 \,cm^3$ of sodium hydroxide solution whose normality is

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Solution:

Volume of monobasic acid $=10 \,cm ^{3}$

Normality of monobasic acid $=0.1 \,N$

Volume of $NaOH$ solution $=15 \,cm ^{3}$

Normality of $NaOH$ solution $=? $

$N_{1} V_{1}=N_{2}\, V_{2}$

(for monobasic acid ) (for $NaOH$ )

$10 \times 0.1\, N=15 \times N_{2}$

$N_{2}=\frac{1 N}{15}=0.066\, N$