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Q.
10.30 mg of $O_{2}$ is dissolved into a liter of sea water of density 1.03 g/mL. The concentration of $O_{2}$ in ppm is
NTA AbhyasNTA Abhyas 2020Some Basic Concepts of Chemistry
Solution:
$
ppm =\frac{ W _{\text {Solute }}}{ W _{\text {Solution }}} \times 100
$
Using the density of the solution and its volume $\left(1 L =1000 mL =1000 cm ^3\right)$, the weight of the solution can be calculated.
$
W _{\text {solution }}=1.03 \times 1000=1030 g
$
Thus, ppm $\frac{10.3 \times 10^{-3} g }{1030 g } \times 10^6=10 ppm$