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Q. $1$ mole of $NO _{2}$ and $2$ moles of $CO$ are enclosed in a one litre vessel to attain the following equilibrium $NO _{2}+ CO \leftrightharpoons NO + CO _{2}$. It was estimated that at the equilibrium, $25 \%$ of initial amount of $CO$ is consumed. The equilibrium constant $K_{p}$ is

Equilibrium

Solution:

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Given : $x=\frac{25}{100} \times 2=0.5$
$\because K_{p}=K_{c}[\Delta n=0]$
$\therefore K_{p}=K_{c}=\frac{[N O]\left[C O_{2}\right]}{\left[N O_{2}\right][C O]}$
$=\frac{x^{2}}{(1-x)(2-x)}=\frac{0.5 \times 0.5}{0.5 \times 0.5}=\frac{1}{3}$