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Q. 1 mole each of $H _3 PO _2, H _3 PO _3$ and $H _3 PO _4$ will neutralize $x$ moles of $NaOH , y$ moles of $Ca ( OH )_2$ and $z$ mole of $Al ( OH )_3$ (assuming all as strong electrolytes). $x, y, z$ are in the ratio of

The p-Block Elements

Solution:

$\underset{\text{monobasic}}{\underset{1}{H _3 PO _2}}+\underset{x}{NaOH} \rightarrow NaH _2 PO _2+2 H _2 O$
$\underset{\text{dibasic }}{H _3 PO _3}+ \underset{y}{Ca ( OH )_2} \rightarrow CaHPO _3+2 H _2 O$
$\underset{\text{tribasic}}{H _3 PO _4}+ \underset{z}{Al ( OH )_3 }\rightarrow AlPO _4+3 H _2 O$
Thus, $x: y: z=1: 1: 1$