1. Tardigrade
  2. Question
  3. Chemistry
  4. 1 mol of X Y( g ) and 0.2 mol of Y( g ) are mixed in 1 L vessel. At equilibrium, 0.6 mol of Y( g ) is present. The value of K for the reaction X Y( g ) leftharpoons X( g )+Y( g ) is

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Q. $1 \,mol$ of $X Y( g )$ and $0.2 \,mol$ of $Y( g )$ are mixed in $1 L$ vessel. At equilibrium, $0.6\, mol$ of $Y( g )$ is present. The value of $K$ for the reaction
$X Y( g ) \rightleftharpoons X( g )+Y( g )$ is

Equilibrium

Solution:

image
At eq. $[ X ]=0.2+x=0.6$
$\therefore x=0.4 \,mol =\frac{0.4}{1}=0.4 \,M$
${[ XY ]=1-0.4 \,mol =0.6\, mol =\frac{0.6}{1}=0.6\, M }$
${[ X ]=x=0.4=\frac{0.4}{1}=0.4 \,M }$
$K=\frac{[ X ][ Y ]}{[ XY ]}=\frac{0.4 \times 0.6}{0.6}=0.4 \,mol\, L ^{-1}$