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Q.
1 M and 2.5 litre NaOH solution mixed with another 0.5 M and 3 litre NaOH solution. Then find out molarity of resultant solution : -
AIPMTAIPMT 1980Solutions
Solution:
Mole of $2.5 L$ of $1 M NaOH =2.5 \times 1=2.5$
Mole of $3.0 L$ of $0.5 M NaOH =3.0 \times 0.5=1.5$
Total moles of $NaOH$ in solution $=2.5+1.5=4.0$
(Total volume of solution $=2.5+3.0=5.5 L$ )
Thus, $M _{1} \times V _{1}= M _{2} \times V _{2}$
$4.0= M _{2} \times 5.5$
Molarity of resultant solution $= M _{2}=\frac{4.0}{5.5}=0.73 M$