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Q. $1\, M$ and $2.5\,L\,NaOH$ solution mixed with another $0.5\,M$ and $ 3\,L\,NaOH$ solution. Then find out molarity of resultant solution

Punjab PMETPunjab PMET 2007Solutions

Solution:

Moles of $2.5\, L$ of $1\, M\, NaOH =2.5 \times 1=2.5$
Moles of $3.0\, L$ of $0.5\, M\, NaOH =3.0 \times 0.5=1.5$
Total moles of $NaOH$ in solution $=2.5+1.5=4.0$
(Total volume of solution $=2.5+3.0=5.5 L$ )
Thus
$M_{1} \times V_{1}=M_{2} \times V_{2}$
$4.0=M_{2} \times 5.5$
$\therefore $ molarity of resultant solution $=M_{2}=\frac{4.0}{5.5} M$
$\approx 0.73\, M$