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Q. $1 \,L$ aqueous solution of $H _{2} SO _{4}$ contains $0.02$ $m mol H _{2} SO _{4} .50 \%$ of this solution is diluted with deionized water to give $1 L$ solution $(A)$. In solution $(A)$, $0.01 \,m$ mol of $H _{2} SO _{4}$ are added. Total $m$ mols of $H _{2} SO _{4}$ in the final solution is _________$\times 10^{3} m \,mols$.

JEE MainJEE Main 2022Some Basic Concepts of Chemistry

Solution:

$n _{ H _{2} SO _{4}}$ in $Sol ^{ n } A =50 \%$ of original solution $=0.01 \,m \,mol$.
$ n _{ H _{2} SO _{4}} $ in Final solution $=0.01+0.01 $
$=0.02 \,mmol $
$=0.00002 \times 10^{3} mmol$
The answer $0$