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  4. 1 kg of NaOH solution contains 4 g of NaOH. The approximate concentration of the solution is :

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Q. $1\, kg$ of $NaOH$ solution contains $4\, g$ of $NaOH$. The approximate concentration of the solution is :

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Solution:

Molecular mass of $NaOH =23+17=40$
Hence, molality $(m)=\frac{4}{40 \times 0.996}=0.1$