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  4. [(-1+ cot 23°)(-1+ cot 22°)(-1+ cot 29°)(-1+ cot . .16°) ] is equal to

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Q. $\left[\left(-1+\cot 23^{\circ}\right)\left(-1+\cot 22^{\circ}\right)\left(-1+\cot 29^{\circ}\right)(-1+\cot \right.$ $\left.16^{\circ}\right)$ ] is equal to

Trigonometric Functions

Solution:

if $A+B=45^{\circ}$,
then $(\cot B-1)(\cot A-1)=2$