Question

$1$ ampere current is equivalent to

• A. $6.25 \times 10^{18}$ electrons $s^{-1}$
• B. $2.25 \times 10^{18}$ electrons $s^{-1}$
• C. $6.25 \times 10^{14}$ electrons $s^{-1}$
• D. $2.25 \times 10^{14}$ electrons $s^{-1}$

Answer 1

Answer: (A)

$Q=It$ also $Q=ne \quad\left[e=1.6 \times 10^{-19}\,C\right]$
$\therefore ne=It$ or $n=\frac{It}{e}=\frac{1\,A \times 1 \,s}{1.6 \times 10^{-19}}$
$=6.25 \times 10^{18}$ electrons $s^{-1}$