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Q. $1$ a.m.u. in terms of energy is :

Haryana PMTHaryana PMT 2001

Solution:

According to Einstein's mass energy equivalence, $E = mc ^{2}$ where $c =$ velocity of light.
So, $E =1.66 \times 10^{-27} \times\left(3 \times 10^{8}\right)^{2}=14.94 \times 10^{-11} J$
$E =\frac{14.94 \times 10^{-11}}{1.6 \times 10^{-19}} eV \quad$ where $1 eV =1.6 \times 10^{-19} J$
$E =931 \times 10^{6} eV =931 MeV$