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Chemistry
1.70 g AgNO 3(a q) reacts with 5.85 g NaCl (a q) to form AgCl (white ppt)
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Q. $1.70\, g\, AgNO _3(a q)$ reacts with $5.85 \,g \,NaCl (a q)$ to form $AgCl$ (white ppt)
Some Basic Concepts of Chemistry
A
$14.35 \,g$
B
$0.1435 \,g$
C
$1.435\, g$
D
$5.85 \,g$
Solution:
$1.70\, g \,AgNO _3$ gives $1.435 \,g\, AgCl$
$5.85 \,g\, NaCl$ gives $14.35\, g\, AgCl$
Thus, $AgNO _3$ is the limiting reactant
$AgCl$ formed $=1.435 \,g$