1. Tardigrade
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  3. Chemistry
  4. 1.575 g of oxalic acid ( COOH )2 x H 2 O are dissolved in water and the volume made upto 250 ml. On titration 8.34 ml of this solution requires 12.5 ml of N / 15 NaOH solution, for complete neutralization. Calculate x.

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Q. $1.575 \,g$ of oxalic acid $( COOH )_{2} x H _{2} O$ are dissolved in water and the volume made upto $250\, ml$. On titration $8.34\, ml$ of this solution requires $12.5\, ml$ of $N / 15\, NaOH$ solution, for complete neutralization. Calculate $x$.

Redox Reactions

Solution:

Meq. of oxalic acid in $8.34\, ml =$ meq of $NaOH$
$=12.5 \times \frac{1}{15}$
$\therefore $ Meq of oxalic acid in $250 \,ml$
$ =12.5 \times \frac{1}{15} \times \frac{250}{8.34}=24.98$
$\therefore \frac{1.575}{90+\frac{18 x}{2}} \times 1000=24.98, x=2$