1. Tardigrade
  2. Question
  3. Mathematics
  4. (1/4)[√3 cos 23°- sin 23°]=

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. $\frac{1}{4}\left[\sqrt{3} \cos 23^{\circ}-\sin 23^{\circ}\right]=$

Trigonometric Functions

Solution:

$\frac{1}{4}\left\{\sqrt{3} \cos 23^{\circ}-\sin 23^{\circ}\right\}$
$=\frac{1}{2}\left\{\cos 30^{\circ} \cos 23^{\circ}-\sin 30^{\circ} \sin 23^{\circ}\right\}$
$=\frac{1}{2} \cos \left\{30^{\circ}+23^{\circ}\right\}=\frac{1}{2} \cos 53^{\circ}$