1. Tardigrade
  2. Question
  3. Chemistry
  4. 1.22 g C6H5COOH is added into the 100 g solvent CH3COCH3 where data of Δ Tb and Kb are given as: ΔTb = 0.17, solute by Kb = 1.7 K kg/mol Find out the molecular weight (g/mol) of the solute in the solution by interpreting the result.

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Q. 1.22 g C6H5COOH is added into the 100 g solvent CH3COCH3 where data of Δ Tb and Kb are given as:
ΔTb = 0.17, solute by Kb = 1.7 K kg/mol
Find out the molecular weight (g/mol) of the solute in the solution by interpreting the result.

NTA AbhyasNTA Abhyas 2022

Solution:

$\Delta \text{T}_{\text{b}} = \text{0.17} = \text{K}_{\text{b}} \cdot \text{m}$
$\text{0.17} = \text{1.7} \times \frac{\text{1.22/M}}{\text{100/1000}}$
M = 122 g/mole
Benzoic acid is not associated or dissociated.