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Q. $1.2\,g$ of $Mg$ (at. mass $24$ ) will produce $MgO$ equal to

ManipalManipal 2018

Solution:

$\because 24 \,g$ of Mg produce $MgO =1\ mol$
$\therefore 1.2\ g$ of $Mg$ will produce $MgO =\frac{1 \times 1.2}{24}=0.05 \,mol$